$(x-1)^2=4(y-2)$, vertex $(1,2)$, focus $(1,3)$, directrix $y=1$, see graph.
Work Step by Step
Step 1. Rewriting the equation as $x^2-2x+1=4y-9+1$ or $(x-1)^2=4(y-2)$, we have $4p=4$ and $p=1$ with the parabola opening upwards and vertex $(1,2)$. Step 2. We can find the focus at $(1,3)$ and directrix as $y=1$ Step 3. We can graph the parabola as shown in the figure.