Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 997: 43

Answer

$(x-1)^2=4(y-2)$, vertex $(1,2)$, focus $(1,3)$, directrix $y=1$, see graph.
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Work Step by Step

Step 1. Rewriting the equation as $x^2-2x+1=4y-9+1$ or $(x-1)^2=4(y-2)$, we have $4p=4$ and $p=1$ with the parabola opening upwards and vertex $(1,2)$. Step 2. We can find the focus at $(1,3)$ and directrix as $y=1$ Step 3. We can graph the parabola as shown in the figure.
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