$(y-1)^2=8x$, vertex $(0,1)$, focus $(2,1)$, directrix $x=-2$, see graph.
Work Step by Step
Step 1. Rewriting the equation as $y^2-2y+1=8x$ or $(y-1)^2=8x$, we have $4p=8$ and $p=2$ with the parabola opening to the right and vertex $(0,1)$. Step 2. We can find the focus at $(2,1)$ and directrix as $x=-2$ Step 3. We can graph the parabola as shown in the figure.