domain $[-6,\infty)$, range $(-\infty, \infty)$, not a function.
Work Step by Step
Step 1. Rewrite the equation as $y^2-2y+1=x+5+1$ or $(y-1)^2=x+6$ We see that the parabola opens to the right with a vertex at $(-6,1)$. Step 2. We can find the domain as $[-6,\infty)$ and range as $(-\infty, \infty)$ Step 3. The relation is not a function as it will fail a vertical line test.