Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 997: 24

Answer

$x^2=-60y$

Work Step by Step

Standard form of a parabola is given as: $x^2=4py$ ...(1) Formula to find focus is: $F(0,p)$ and formula to find directrix is: $y=-p$ As we are given that focus is: $(0,-15)$ and directrix is: $y=15$ Plug all these data in equation (1), we have: $p=-15$ Thus, $x^2=4(-15)y \implies x^2=-60y$
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