Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 997: 26



Work Step by Step

General form of a horizontal parabola is given as: $(y-k)^2=4p(x-k)$...(1) Here, $\text{Vertex}=(h,k)$ and focus is: $(h+p, k)$ As we are given $\text{Vertex}=(5,-2)$ and focus is: $(7,-2)$ Thus, $h=5,k=-2$ and $h+p=7 \implies 5+p=7$ or, $p=2$ From equation (1), we have $(y-(-2))^2=4(2)(x-5)$ or, $(y+2)^2=8(x-5)$
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