vertex $(-2,-1)$, focus $(-2,0)$, directrix $y=-2$, see graph.
Work Step by Step
Step 1. Given $(x+2)^2=4(y+1)$, we have $4p=4$ and $p=1$ with the parabola opening upwards and vertex $(-2,-1)$. Step 2. We can find the focus at $(-2,0)$ and directrix as $y=-2$ Step 3. We can graph the parabola as shown in the figure.