Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 997: 36

Answer

vertex $(-2,-1)$, focus $(-2,0)$, directrix $y=-2$, see graph.

Work Step by Step

Step 1. Given $(x+2)^2=4(y+1)$, we have $4p=4$ and $p=1$ with the parabola opening upwards and vertex $(-2,-1)$. Step 2. We can find the focus at $(-2,0)$ and directrix as $y=-2$ Step 3. We can graph the parabola as shown in the figure.
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