## Precalculus (6th Edition) Blitzer

See figure, $(-5,0)$ and $(4,\pm3)$
Step 1. Graph the given equations $\begin{cases} x=y^2-5 \\x^2+y^2=25 \end{cases}$ as shown in the figure. Step 2. We can identify the intersection points as $(-5,0)$ and $(4,\pm3)$ Step 3. Check the solutions in the first equation: $(-5)=(0)^2-5$ and $(4)=(\pm3)^2-5$ Step 4. Check the solutions in the second equation: $(-5)^2+(0)^2=25$ and $(4)^2+(\pm3)^2=25$