Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 997: 66

Answer

See figure, $(-5,0)$ and $(4,\pm3)$
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Work Step by Step

Step 1. Graph the given equations $\begin{cases} x=y^2-5 \\x^2+y^2=25 \end{cases}$ as shown in the figure. Step 2. We can identify the intersection points as $(-5,0)$ and $(4,\pm3)$ Step 3. Check the solutions in the first equation: $ (-5)=(0)^2-5$ and $ (4)=(\pm3)^2-5$ Step 4. Check the solutions in the second equation: $(-5)^2+(0)^2=25$ and $(4)^2+(\pm3)^2=25$
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