Answer
See figure, $(-5,0)$ and $(4,\pm3)$
Work Step by Step
Step 1. Graph the given equations
$\begin{cases} x=y^2-5 \\x^2+y^2=25 \end{cases}$
as shown in the figure.
Step 2. We can identify the intersection points as $(-5,0)$ and $(4,\pm3)$
Step 3. Check the solutions in the first equation:
$ (-5)=(0)^2-5$ and $ (4)=(\pm3)^2-5$
Step 4. Check the solutions in the second equation:
$(-5)^2+(0)^2=25$ and $(4)^2+(\pm3)^2=25$
