vertex $(0,-1)$, focus $(-2,-1)$, directrix $x=2$, see graph.
Work Step by Step
Step 1. Given $(y+1)^2=-8x$, we have $4p=-8$ and $p=-2$ with the parabola opening to the left and vertex $(0,-1)$. Step 2. We can find the focus at $(-2,-1)$ and directrix as $x=2$ Step 3. We can graph the parabola as shown in the figure.