Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 997: 41

Answer

vertex $(0,-1)$, focus $(-2,-1)$, directrix $x=2$, see graph.

Work Step by Step

Step 1. Given $(y+1)^2=-8x$, we have $4p=-8$ and $p=-2$ with the parabola opening to the left and vertex $(0,-1)$. Step 2. We can find the focus at $(-2,-1)$ and directrix as $x=2$ Step 3. We can graph the parabola as shown in the figure.
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