Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 997: 65


See figure, $(-2,1)$

Work Step by Step

Step 1. Graph the given equations $\begin{cases} x=y^2-3 \\x=y^2-3y \end{cases}$ as shown in the figure. Step 2. We can identify the intersection point as $(-2,1)$ Step 3. Check the solution in the first equation: $(-2)=1^2-3$ Step 4. Check the solution in the second equation: $(-2)=1^2-3(1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.