Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 997: 65

Answer

See figure, $(-2,1)$
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Work Step by Step

Step 1. Graph the given equations $\begin{cases} x=y^2-3 \\x=y^2-3y \end{cases}$ as shown in the figure. Step 2. We can identify the intersection point as $(-2,1)$ Step 3. Check the solution in the first equation: $(-2)=1^2-3$ Step 4. Check the solution in the second equation: $(-2)=1^2-3(1)$
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