Precalculus (6th Edition) Blitzer

See figure, $(-2,1)$
Step 1. Graph the given equations $\begin{cases} x=y^2-3 \\x=y^2-3y \end{cases}$ as shown in the figure. Step 2. We can identify the intersection point as $(-2,1)$ Step 3. Check the solution in the first equation: $(-2)=1^2-3$ Step 4. Check the solution in the second equation: $(-2)=1^2-3(1)$