Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 997: 64

Answer

See graph, $(2,3)$ and $(3,2)$
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Work Step by Step

Step 1. Graph the given equations $\begin{cases} (y-3)^2=x-2 \\ x+y=5 \end{cases}$ as shown in the figure. Step 2. We can identify the intersection points as $(2,3)$ and $(3,2)$ Step 3. Check the solutions in the first equation: $((3)-3)^2=(2)-2=0$ and $((2)-3)^2=(3)-2=1$ Step 4. Check the solutions in the second equation: $(2)+(3)=5$ and $(3)+(2)=5$
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