Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 280: 57


$(x+4)^2+(y-1)^2=25$ $C(-4,1), r=5$ See graph.

Work Step by Step

Step 1. From the given equation $x^2+y^2+8x-2y-8=0$, we have $(x^2+8x+16)+(y^2-2y+1)=16+1+8$ and $(x+4)^2+(y-1)^2=25$ Step 2. We can identify the center and radius of the circle as $C(-4,1), r=5$ Step 3. See graph.
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