## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set: 1

#### Answer

$13$ units

#### Work Step by Step

Use the distance formula $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ to obtain: $d=\sqrt{(2-14)^2+(3-8)^2} \\d=\sqrt{(-12)^2+(-5)^2} \\d=\sqrt{144+25} \\d=\sqrt{169} \\d=13$

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