## Precalculus (6th Edition) Blitzer

$d\approx 2.83$
RECALL: The distance between the points $(x_1, y_1)$ and $x_2, y_2)$ can be found using the distance formula: $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ Solve for the distance between the two points using the formula above to obtain: $d=\sqrt{(0-\sqrt{5})^2+(-\sqrt{3}-0)^2} \\d=\sqrt{(-\sqrt5)^2+(-\sqrt3)^2} \\d=\sqrt{5+3} \\d=\sqrt{8} \\d\approx 2.83$