# Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 280: 28

$\text{midpoint} = (5\sqrt{3}, -4)$

#### Work Step by Step

RECALL: The midpoint of the line segment whose endpoints are $(x_1, y_1)$ and $(x_2, y_2)$ can be found using the midpoint formula: $\text{midpoint}=\left(\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2} \right)$ Use the formula above to obtain: $\text{midpoint} = \left(\dfrac{7\sqrt{3}+3\sqrt{3}}{2}, \dfrac{-6+(-2)}{2}\right)=\left(\dfrac{10\sqrt{3}}{2}, \dfrac{-8}{2}\right) \\\text{midpoint} = (5\sqrt{3}, -4)$

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