#### Answer

$(x-3)^2+(y-2)^2=25$

#### Work Step by Step

RECALL:
The standard equation of a circle whose center is at $(h, k)$ and has a radius of $r$ units is:
$(x-h)^2 + (y-k)^2 = r^2$
The given circle has its center at $(3, 2)$ and a radius of 5 units.
Thus, the standard form of the circle's equation is:
$(x-3)^2+(y-2)^2=5^2
\\(x-3)^2+(y-2)^2=25$