## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 280: 14

#### Answer

$d=3$

#### Work Step by Step

RECALL: The distance between the points $(x_1, y_1)$ and $x_2, y_2)$ can be found using the distance formula: $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ Solve for the distance between the two points using the formula above to obtain: $d=\sqrt{(0-\sqrt{7})^2+(-\sqrt{2}-0)^2} \\d=\sqrt{(-\sqrt7)^2+(-\sqrt2)^2} \\d=\sqrt{7+2} \\d=\sqrt{9} \\d=3$

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