Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 280: 4

Answer

$\approx 8.54$ units

Work Step by Step

Use the distance formula $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ to obtain: $d=\sqrt{(2-(-1))^2+(-3-5)^2} \\d=\sqrt{(2+1)^2+(-8)^2} \\d=\sqrt{3^2+64} \\d=\sqrt{9+64} \\d=\sqrt{73} \\d \approx 8.54$
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