#### Answer

$(x+3)^2+(y+1)^2=3$

#### Work Step by Step

RECALL:
The standard equation of a circle whose center is at $(h, k)$ and has a radius of $r$ units is:
$(x-h)^2 + (y-k)^2 = r^2$
The given circle has its center at $(-3, -1)$ and a radius of $\sqrt3$ units.
Thus, the standard form of the circle's equation is:
$(x-(-3))^2+(y-(-1))^2=(\sqrt3)^2
\\(x+3)^2+(y+1)^2=3$