Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 280: 26


$\left(-\dfrac{2}{5}, -\dfrac{1}{10}\right)$

Work Step by Step

RECALL: The midpoint of the line segment whose endpoints are $(x_1, y_1)$ and $(x_2, y_2)$ can be found using the midpoint formula: $\text{midpoint}=\left(\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2} \right)$ Use the formula above to obtain: $\text{midpoint} = \left(\dfrac{-\frac{2}{5}+(-\frac{2}{5})}{2}, \dfrac{\frac{7}{15}+(-\frac{4}{15})}{2}\right)=\left(\dfrac{-\frac{4}{5}}{2}, \dfrac{-\frac{3}{15}}{2}\right) \\\text{midpoint} = \left(-\dfrac{2}{5}, -\dfrac{3}{30}\right)= \left(-\dfrac{2}{5}, -\dfrac{1}{10}\right)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.