$C(-3,2), r=2$. See graph. Domain $[-5,-1]$ and Range $[0,4]$ .
Work Step by Step
Step 1. Given the equation $(x+3)^2+(y-2)^2=4$, comparing with the standard form for a circle, we can identify the center and radius of the circle as $C(-3,2), r=2$. Step 2. See graph for the equation as shown in the figure. Step 3. Based on the graph, we can identify: Domain $[-5,-1]$ and Range $[0,4]$ .