## Precalculus (6th Edition) Blitzer

$C(0,1), r=1$ . See graph . Domain $[-1,1]$ and Range $[0,2]$ .
Step 1. Given the equation $(x)^2+(y-1)^2=1$, comparing with the standard form for a circle, we can identify the center and radius of the circle as $C(0,1), r=1$ . Step 2. See graph for the equation as shown in the figure. Step 3. Based on the graph, we can identify: Domain $[-1,1]$ and Range $[0,2]$ .