Answer
$2(x+1)(4x-1)$
Work Step by Step
Factor out $2$.
$8x^2+6x-2=2(4x^2+3x-1)$
Rewrite $3x$ as $4x-1x$.
$=2(4x^2+4x-1x-1)$
Group the first two terms together and group the last two terms together to obtain:
$=2[(4x^2+4x)+(-1x-1)]$
Factor out the GCF in each group.
$=2[4x(x+1)-1(x+1)]$
Factor out $(x+1)$.
$=2(x+1)(4x-1)$
Hence, the completely factored form of the given expression is $2(x+1)(4x-1)$.
