Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A30: 88

Answer

$(x+6)^2$

Work Step by Step

The leading coefficient is $1$ so just look for factors of $36$ whose sum is equal to the coefficient of the middle term $(12)$. The factors are $6$ and $6$. Rewrite the middle term $12x$ as $6x+6x$ to obtain: $x^2+12x+36=x^2+6x+6x+36$ Group the first two terms and group the last two terms to obtain: $=(x^2+6x)+(6x+36)$ Factor out the GCF in each group. $=x(x+6)+6(x+6)$ Factor out $(x+6)$. $=(x+6)(x+6)$ $=(x+6)^2$ Hence, the completely factored form of the given expression is $(x+6)^2$.
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