Answer
$x^5(x+1)(x-1)$
Work Step by Step
Factor out the GCF $x^5$.
$x^7-x^5\\
=x^5(x^2-1)$
$=x^5(x^2-1^2)$
Use special formula $a^2-b^2=(a+b)(a-b)$ with $a=x$ and $b=1$ to obtain:
$=x^5(x+1)(x-1)$
Hence, the completely factored form of the given expression is $x^5(x+1)(x-1)$.
