Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A30: 83

Answer

$(x-7)(x-3)$

Work Step by Step

The leading term's coefficient is $1$ so just look for factors of $21$ whose sum is equal to the middle term's coefficient which is $-10$. The factors are $-7$ and $-3$. Rewrite the middle term ($-10x$) as $-7x-3x$ to obtain: $x^2-10x+21=x^2-7x-3x+21$ Group first two terms and the group the last two terms together. $=(x^2-7x)+(-3x+21)$ Factor out the GCF in each group. $=x(x-7)-3(x-7)$ Factor out $(x-7)$. $=(x-7)(x-3)$ Hence, the completely factored form of the given expression is $(x-7)(x-3)$.
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