## Precalculus (10th Edition)

$x^{2}+8x+16$
The standard form of a polynomial is $a_{n}x^{n}+a_{n}x^{n-1}+\cdots+a_{1}x+a_{0}$ (written in order, highest degree first. If a term is missing, it means that the coefficient is 0) --- Use the perfect square formula $(A+B)^{2}=A^{2}+2AB+B^{2}$ $(x+4)^{2}=x^{2}+2\cdot x\cdot 4+4^{2}$ = $x^{2}+8x+16$