## Precalculus (10th Edition)

$(x+1)(x+10)$
To factor trinomials in the form $x^{2}+bx+c$, we look for two factors of $c$, say $m$ and $n$, whose sum is equal to $b$. The factored form of the trinomial then would be $(x+m)(x+n)$. The given trinomial has $c=10$ and $b=11$. The two factors of $10$ whose sum is $11$ are $1$ and $10$. Thus, the factored form of the given trinomial is $\color{blue}{(x+1)(x+10)}$.