Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A30: 84

Answer

$(x-4)(x-2)$

Work Step by Step

The leading term's coefficient is $1$ so just look for factors of $8$ whose sum is equal to the middle term's coefficient which is $-6$. The factors are $-4$ and $-2$. Rewrite the middle term ($-6x$) as $-4x-2x$ to obtain: $x^2-6x+8=x^2-4x-2x+8$ Group the first two terms together and the last two terms together. $=(x^2-4x)+(-2x+8)$ Factor out the GCF in each group. $=x(x-4)-2(x-4)$ Factor out $(x-4)$. $=(x-4)(x-2)$ Hence, the completely factored form of the given expression is $(x-4)(x-2)$.
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