Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A30: 105

Answer

$(4x+3)^2$

Work Step by Step

Rewrite $24x$ as $12x+12x$. $16x^2+24x+9=16x^2+12x+12x+9$ Group the first two terms together and the last two terms together: $=(16x^2+12x)+(12x+9)$ Factor out the GCF in each group. $=4x(4x+3)+3(4x+3)$ Factor out $(4x+3)$. $=(4x+3)(4x+3)$ $=(4x+3)^2$ Hence, the completely factored form of the given expression is $(4x+3)^2$.
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