Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A30: 110

Answer

$(3y+4)(3y-1)$

Work Step by Step

Rewrite $9y$ as $12y-3y$. $9y^2+9y-4=9y^2+12y-3y-4$ Group the first two terms together and group the last two terms together. $=(9y^2+12y)+(-3y-4)$ Factor out the GCF in each group. $=3y(3y+4)+(-1)(3y+4)$ $=3y(3y+4)-(3y+4)$ Factor out $(3y+4)$. $=(3y+4)(3y-1)$ Hence, the completely factored form of the given expression is $(3y+4)(3y-1)$.
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