Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A30: 77



Work Step by Step

The given expression is equivalent to $x^2-6^2$, which is a difference of two squares. Factor using the formula for a difference of squares, which is $A^{2}-B^{2}=(A-B)(A+B)$, to obtain $x^{2}-6^{2}=(x+6)(x-6)$
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