Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A30: 95

Answer

$(2x+3)^2$

Work Step by Step

Rewrite $12x$ as $6x+6x$. $4x^2+12x+9=4x^2+6x+6x+9$ Group the first two terms together and group the last two terms together. $=(4x^2+6x)+(6x+9)$ Factor out the GCF in each group. $=2x(2x+3)+3(2x+3)$ Factor out $(2x+3)$. $=(2x+3)(2x+3)$ $=(2x+3)^2$ Hence, the completely factored form of the given expression is $(2x+3)^2$.
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