Answer
$-\infty $
Work Step by Step
When $ x $ approaches -8 from the right then $ x+8$ approaches 0 from the left because $ x+8<0$, so
$$\lim _{x \rightarrow-8^{+}} \frac{2x}{ x+8}= - \infty $$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.