Answer
$$-1$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow \infty} \frac{2+\sqrt{x}}{2-\sqrt{x}} : \frac{\sqrt{x}}{\sqrt{x}}&=\lim _{x \rightarrow \infty} \frac{\frac{2}{\sqrt{x}}+1}{\frac{2}{\sqrt{x}}-1}\\
&=\frac{\lim _{x \rightarrow \infty}\frac{2}{\sqrt{x}}+\lim _{x \rightarrow \infty}(1)}{\lim _{x \rightarrow \infty}\frac{2}{\sqrt{x}}-\lim _{x \rightarrow \infty}(1)}\\
&=\frac{0+1}{0-1}\\
&=-1
\end{align*}