Answer
$$-1$$
Work Step by Step
Since
\begin{align*}
\lim _{t \rightarrow-\infty} \frac{2-t+\sin t}{t+\cos t}&=\lim _{t \rightarrow-\infty} \frac{\frac{2}{t}-1+\frac{\sin t}{t}}{1+\frac{\cos t}{t}}\\
&=\frac{\lim _{t \rightarrow-\infty}\frac{2}{t}-\lim _{t \rightarrow-\infty}(1)+\lim _{t \rightarrow-\infty}\frac{\sin t}{t}}{\lim _{t \rightarrow-\infty}(1)+\lim _{t \rightarrow-\infty}\frac{\cos t}{t}}\\
&=\frac{0-1+0}{1+0}\\
&=-1
\end{align*}