Answer
$$0$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow \infty} \frac{2 \sqrt{x}+x^{-1}}{3 x-7} : \frac{x}{x}&=\lim _{x \rightarrow \infty} \frac{\frac{2}{\sqrt{x}}+\frac{1}{x^{2}}}{3-\frac{7}{x}}\\
&= \frac{\lim _{x \rightarrow \infty} \frac{2}{\sqrt{x}}+\lim _{x \rightarrow \infty} \frac{1}{x^{2}}}{\lim _{x \rightarrow \infty} 3-\lim _{x \rightarrow \infty} \frac{7}{x}}\\
&= \frac{0+0}{3-0}\\
&=0
\end{align*}