Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.6 - Limits Involving Infinity; Asymptotes of Graphs - Exercises 2.6 - Page 97: 40

Answer

$\infty $

Work Step by Step

When $ x $ approaches 3 from the left then $ x-3$ approaches 0 from the right because $ x-3>0$. Thus: $$\lim _{x \rightarrow 3^{+}} \frac{1}{ x-3}= \infty $$
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