Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.6 - Limits Involving Infinity; Asymptotes of Graphs - Exercises 2.6 - Page 97: 37

Answer

$\infty $

Work Step by Step

Since the numerator is positive and the denominator goes to zero from the right, thus $$\lim _{x \rightarrow 0^{+}} \frac{1}{3 x}=\infty $$
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