Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.5 Conic Sections - Exercises - Page 636: 59


$$ r=\frac{-12}{5+6 \cos \theta}. $$

Work Step by Step

Since $e=1.2$ and $d=-2$, then the polar equation in the standard form is $$ r=\frac{e d}{1+e \cos \theta}=\frac{-2.4}{1+1.2 \cos \theta}=-\frac{24}{10+12 \cos \theta}. $$ Which simplifies to $$r=\frac{-12}{5+6 \cos \theta}.$$
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