Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.5 Conic Sections - Exercises - Page 636: 11


$$ \left(\frac{x}{5}\right)^{2}+\left(\frac{y}{7}\right)^{2}=1. $$

Work Step by Step

Since the vertices are at $(\pm 5,0)$ and $(0,\pm7)$, then we have $$a=5, \quad b=7$$ and hence the ellipse is centered at the origin and has the equation $$ \left(\frac{x}{5}\right)^{2}+\left(\frac{y}{7}\right)^{2}=1. $$
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