Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.5 Conic Sections - Exercises - Page 636: 23


$$y= \frac{1}{20}x^2 .$$

Work Step by Step

The vertex is at $(0,0)$ and the directrix is $y=-5=-c$; hence $c=5$. The parabola is vertical, opens upward, and has the equation $$y=\frac{1}{4c}x^2=\frac{1}{20}x^2 .$$
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