Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.5 Conic Sections - Exercises - Page 636: 22


$$y = \frac{1}{8}x^2 .$$

Work Step by Step

The vertex is at $(0,0)$ and the focus is at $( 0,2)$; hence, $c=2$. The parabola is vertical and opens upward and has the equation $$y =\frac{1}{4c}x^2=\frac{1}{8}x^2 .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.