Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.5 Conic Sections - Exercises - Page 636: 52

Answer

$$ r =-\frac{3}{2+ \cos \theta}. $$

Work Step by Step

The polar equation of the conic section of eccentricity $e \gt0$, with focus at the origin and directrix $x = d$ is $$ r=\frac{e d}{1+e \cos \theta}. $$ Now, since $e=1/2$ and $x=-3$, then the polar equation is $$ r=\frac{-3/2}{1+(1/2) \cos \theta}=-\frac{3}{2+ \cos \theta}. $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.