#### Answer

Parabola with:
- focus $F = (4, \frac{1}{16}),$
- directrix $y = −\frac{1}{16}$,
- vertex $ (4, 0).$

#### Work Step by Step

The equation $y=4(x-4)^2$ is a parabola and by comparing it with the standard equation $y-k=\frac{1}{4c}(x-h)^2$, we get
$4=\frac{1}{4c}$
$c=\frac{1}{16}$
Thus, we have:
- Focus $F = (4, \frac{1}{16}),$
- Directrix $y = −\frac{1}{16}$,
- Vertex at the origin $ (4, 0).$