#### Answer

$$ \left(\frac{y}{6}\right)^{2}-\left(\frac{x}{12\sqrt 2}\right)^{2}=1. $$

#### Work Step by Step

Since the vertices are $(0,\pm 6)$ and $e=3$, then the axis of the hyperbola is the y-axis and then $b=6$, moreover, $ e=\frac{c}{b}=\frac{c}{6}=3 $, and hence $c=18 $ and $a=\sqrt{c^2-b^2}=\sqrt{18^2-6^2}=12\sqrt{2}$. Hence the equation of the hyperbola is given by
$$ \left(\frac{y}{6}\right)^{2}-\left(\frac{x}{12\sqrt 2}\right)^{2}=1. $$