Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.5 Conic Sections - Exercises - Page 636: 27


$$x= \frac{1}{8}y^2 .$$

Work Step by Step

The focus is at $(2,0)$ and the directrix is $x=-2=-c$, hence $c=2$. The parabola is horizontal, opens to the right, and has the equation $$x=\frac{1}{4c}y^2=\frac{1}{8}y^2 .$$
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