## Calculus (3rd Edition)

$$y = 3x^2.$$
The vertex is at $(0,0)$ and the focus is at $(\frac{1}{12},0)$, hence $c=\frac{1}{12}$. The parabola is horizontal and opens to the right and has the equation $$y =\frac{1}{4c}x^2=\frac{12}{4}x^2=3x^2.$$