Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.5 Conic Sections - Exercises - Page 636: 21


$$y = 3x^2.$$

Work Step by Step

The vertex is at $(0,0)$ and the focus is at $(\frac{1}{12},0)$, hence $c=\frac{1}{12}$. The parabola is horizontal and opens to the right and has the equation $$y =\frac{1}{4c}x^2=\frac{12}{4}x^2=3x^2.$$
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