## Calculus (3rd Edition)

- the vertices are $( \pm 2,0)$ - the foci are $( \pm \sqrt{40/9},0)$ - the center is $(0,0)$ - asymptotes $y=\pm \frac{2/3}{2}(x)=\pm \frac{1}{3}x$.
The equation $$\left(\frac{x}{2}\right)^{2}-\left(\frac{y}{2/3}\right)^{2}=1$$ is a hyperbola with $a=2, b=2/3$ and hence $c=\sqrt{a^2+b^2}=\sqrt{40/9}$. So, we have the vertices are $( \pm 2,0)$ the foci are $( \pm \sqrt{40/9},0)$ the center is $(0,0)$ asymptotes $y=\pm \frac{2/3}{2}(x)=\pm \frac{1}{3}x$.