Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 12 - Vector-Valued Functions - 12.5 Exercises - Page 860: 31

Answer

\[K = \frac{1}{a}\]

Work Step by Step

\[\begin{gathered} {\mathbf{r}}\left( t \right) = a\cos \omega t{\mathbf{i}} + a\sin \omega t{\mathbf{j}} \hfill \\ {\text{By Theorem 12}}{\text{.8 }} \hfill \\ {\text{If }}C{\text{ is a smooth curve given by }}{\mathbf{r}}\left( t \right),{\text{ then the curvature }}K{\text{ of}} \hfill \\ C{\text{ at }}t{\text{ is }}K = \frac{{\left\| {{\mathbf{r}}'\left( t \right) \times {\mathbf{r}}''\left( t \right)} \right\|}}{{{{\left\| {{\mathbf{r}}'\left( t \right)} \right\|}^3}}} \hfill \\ {\mathbf{r}}\left( t \right) = a\cos \omega t{\mathbf{i}} + a\sin \omega t{\mathbf{j}} \hfill \\ {\mathbf{r}}'\left( t \right) = - a\omega \sin \omega t{\mathbf{i}} + a\omega \cos \omega t{\mathbf{j}} \hfill \\ {\mathbf{r}}''\left( t \right) = - a{\omega ^2}\cos \omega t{\mathbf{i}} - a{\omega ^2}\sin \omega t{\mathbf{j}} \hfill \\ \hfill \\ {\mathbf{r}}'\left( t \right) \times {\mathbf{r}}''\left( t \right) = \left| {\begin{array}{*{20}{c}} {\mathbf{i}}&{\mathbf{j}}&{\mathbf{k}} \\ { - a\omega \sin \omega t}&{a\omega \cos \omega t}&0 \\ { - a{\omega ^2}\cos \omega t}&{ - a{\omega ^2}\sin \omega t}&0 \end{array}} \right| \hfill \\ {\mathbf{r}}'\left( t \right) \times {\mathbf{r}}''\left( t \right) = \left| {\begin{array}{*{20}{c}} {a\omega \cos \omega t}&0 \\ { - a{\omega ^2}\sin \omega t}&0 \end{array}} \right|{\mathbf{i}} - \left| {\begin{array}{*{20}{c}} { - a\omega \sin \omega t}&0 \\ { - a{\omega ^2}\cos \omega t}&0 \end{array}} \right|{\mathbf{j}} \hfill \\ + \left| {\begin{array}{*{20}{c}} { - a\omega \sin \omega t}&{a\omega \cos \omega t} \\ { - a{\omega ^2}\cos \omega t}&{ - a{\omega ^2}\sin \omega t} \end{array}} \right|{\mathbf{k}} \hfill \\ {\mathbf{r}}'\left( t \right) \times {\mathbf{r}}''\left( t \right) = \left( {{a^2}{\omega ^3}{{\sin }^2}\omega t + {a^2}{\omega ^3}{{\cos }^2}\omega t} \right){\mathbf{k}} \hfill \\ {\mathbf{r}}'\left( t \right) \times {\mathbf{r}}''\left( t \right) = {a^2}{\omega ^3}\left( {{{\sin }^2}\omega t + {{\cos }^2}\omega t} \right){\mathbf{k}} \hfill \\ {\mathbf{r}}'\left( t \right) \times {\mathbf{r}}''\left( t \right) = {a^2}{\omega ^3}{\mathbf{k}} \hfill \\ \left\| {{\mathbf{r}}'\left( t \right) \times {\mathbf{r}}''\left( t \right)} \right\| = {a^2}{\omega ^3} \hfill \\ and \hfill \\ \left\| {{\mathbf{r}}'\left( t \right)} \right\| = \left\| { - a\omega \sin \omega t{\mathbf{i}} + a\omega \cos \omega t{\mathbf{j}}} \right\| \hfill \\ \left\| {{\mathbf{r}}'\left( t \right)} \right\| = \sqrt {{a^2}{\omega ^2}\left( {{{\sin }^2}\omega t + {{\cos }^2}\omega t} \right)} \hfill \\ \left\| {{\mathbf{r}}'\left( t \right)} \right\| = a\omega \hfill \\ {\text{Therefore,}} \hfill \\ K = \frac{{\left\| {{\mathbf{r}}'\left( t \right) \times {\mathbf{r}}''\left( t \right)} \right\|}}{{{{\left\| {{\mathbf{r}}'\left( t \right)} \right\|}^3}}} = \frac{{{a^2}{\omega ^3}}}{{{{\left( {a\omega } \right)}^3}}} \hfill \\ K = \frac{1}{a} \hfill \\ \end{gathered} \]
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