Answer
$\frac{{{x^2}}}{2} + \sin x + C$
Work Step by Step
$$\eqalign{
& \int {\left( {x + \cos x} \right)} dx \cr
& {\text{Use the sum rule for integration}} \cr
& = \int x dx + \int {\cos x} dx \cr
& {\text{Apply: }}\int {{x^n}} dx = \frac{{{x^{n + 1}}}}{{n + 1}} + C{\text{ and }}\int {\cos xdx} = \sin x + C \cr
& = \frac{{{x^{1 + 1}}}}{{1 + 1}} + \sin x + C \cr
& {\text{Simplify}} \cr
& = \frac{{{x^2}}}{2} + \sin x + C \cr} $$